5^1=2x+5/x+5

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Solution for 5^1=2x+5/x+5 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

5^1 = 2*x+5/x+5 // - 2*x+5/x+5

5^1-(2*x)-(5/x)-5 = 0

5-2*x-5*x^-1-5 = 0

-2*x^1-5*x^-1 = 0

(-2*x^2-5*x^0)/(x^1) = 0 // * x^2

x^1*(-2*x^2-5*x^0) = 0

x^1

-2*x^2-5 = 0

-2*x^2-5 = 0

DELTA = 0^2-(-5*(-2)*4)

DELTA = -40

DELTA < 0

x in { } 

x belongs to the empty set

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